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Kamis, 28 Oktober 2010

VLSM

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Soal VLSM
1.       Network Awal  = 192.168.0.0/24
Tentukan alokasi / range dari:
-          52 PC
-          62 PC
-          46 PC
-          23 PC

2.       Network Awal  = 192.128.12.0/22
Tentukan alokasi / range dari:
-          201 PC
-          205 PC
-          126 PC
-          128 PC

3.       Network Awal  = 192.168.64.0/23
Tentukan alokasi / range dari:
-          64 PC
-          23 PC
-          30 PC
-          12 PC
-          100 PC


Jawaban VLSM

1.       -Langkah 1
NetA = 52 + 2 = 54   >>>       64                               mask = /26 : 255.255.255.192
NetB = 62 + 2 = 64   >>>       64                               mask = /26 : 255.255.255.192
NetC = 46 + 2 = 48   >>>       64                               mask = /26 : 255.255.255.192
NetD = 23 + 2 = 25   >>>         32                             mask = /27 : 255.255.255.224

                                                   Total : 134
                -Langkah 2 & Langkah 3
NetA = 192.168.0.0/26  s/d  192.168.0.63/26
NetB = 192.168.0.64/26  s/d  192.168.0.127/26
Net C= 192.168.0.128/26  s/d  192.168.0.191/26
NetD = 192.168.0.192/27  s/d  192.168.0.223/27

IP sisa = 192.168.0.224  s/d  192.168.1.89 (122 ip)



2.       -Langkah 1
NetA = 201 + 2 = 203   >>>       256                             mask = /24 : 255.255.255.0
NetB = 205 + 2 = 207   >>>       256                             mask = /24 : 255.255.255.0
NetC = 126 + 2 = 128   >>>       128                            mask = /25 : 255.255.255.128
NetD = 127 + 2 = 130   >>>      256                            mask = /24 : 255.255.255.0

                                                          Total : 896
                -Langkah 2 & Langkah 3
NetA = 192.128.12.0/24  s/d  192.128.12.255/24
NetB = 192.128.13.0/24  s/d  192.128.13.255/24
Net C= 192.128.14.0/25  s/d  192.128.14.255/25
NetD = 192.128.15.0/24  s/d  192.128.15.127/24

IP sisa = 192.128.15.128  s/d  192.128.16.225 (128 ip)

 
3.       -Langkah 1
NetA = 64 + 2 = 66   >>>        128                                 mask = /25 : 255.255.255.128
NetB = 23 + 2 = 25   >>>          32                                 mask = /27 : 255.255.255.224
NetC = 30 + 2 = 32   >>>          32                                 mask = /27 : 255.255.255.224
NetD = 12 + 2 = 14   >>>          16                                 mask = /28 : 255.255.255.240
NetE = 100 + 2 = 102 >>>       128                               mask = /25 : 255.255.255.128

                                                        Total : 336
                -Langkah 2 & Langkah 3
NetA = 192.168.64.0/24  s/d  192.168.64.0/24
NetB = 192.168.64.128/24  s/d  192.168.64.255/24
Net C= 192.168.65.0/25  s/d  192.168.65.31/25
NetD = 192.168.65.32/24  s/d  192.168.65.63/24
NetE = 192.168.65.64/24  s/d  192.168.65.79/24

IP sisa = 192.168.65.80  s/d  192.168.65.255 (176 ip)


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