Soal VLSM
1. Network Awal = 192.168.0.0/24
Tentukan alokasi / range dari:
- 52 PC
- 62 PC
- 46 PC
- 23 PC
2. Network Awal = 192.128.12.0/22
Tentukan alokasi / range dari:
- 201 PC
- 205 PC
- 126 PC
- 128 PC
3. Network Awal = 192.168.64.0/23
Tentukan alokasi / range dari:
- 64 PC
- 23 PC
- 30 PC
- 12 PC
- 100 PC
Jawaban VLSM
1. -Langkah 1
NetA = 52 + 2 = 54 >>> 64 mask = /26 : 255.255.255.192
NetB = 62 + 2 = 64 >>> 64 mask = /26 : 255.255.255.192
NetC = 46 + 2 = 48 >>> 64 mask = /26 : 255.255.255.192
NetD = 23 + 2 = 25 >>> 32 mask = /27 : 255.255.255.224
Total : 134
-Langkah 2 & Langkah 3
NetA = 192.168.0.0/26 s/d 192.168.0.63/26
NetB = 192.168.0.64/26 s/d 192.168.0.127/26
Net C= 192.168.0.128/26 s/d 192.168.0.191/26
NetD = 192.168.0.192/27 s/d 192.168.0.223/27
IP sisa = 192.168.0.224 s/d 192.168.1.89 (122 ip)
2. -Langkah 1
NetA = 201 + 2 = 203 >>> 256 mask = /24 : 255.255.255.0
NetB = 205 + 2 = 207 >>> 256 mask = /24 : 255.255.255.0
NetC = 126 + 2 = 128 >>> 128 mask = /25 : 255.255.255.128
NetD = 127 + 2 = 130 >>> 256 mask = /24 : 255.255.255.0
Total : 896
-Langkah 2 & Langkah 3
NetA = 192.128.12.0/24 s/d 192.128.12.255/24
NetB = 192.128.13.0/24 s/d 192.128.13.255/24
Net C= 192.128.14.0/25 s/d 192.128.14.255/25
NetD = 192.128.15.0/24 s/d 192.128.15.127/24
IP sisa = 192.128.15.128 s/d 192.128.16.225 (128 ip)
3. -Langkah 1
NetA = 64 + 2 = 66 >>> 128 mask = /25 : 255.255.255.128
NetB = 23 + 2 = 25 >>> 32 mask = /27 : 255.255.255.224
NetC = 30 + 2 = 32 >>> 32 mask = /27 : 255.255.255.224
NetD = 12 + 2 = 14 >>> 16 mask = /28 : 255.255.255.240
NetE = 100 + 2 = 102 >>> 128 mask = /25 : 255.255.255.128
Total : 336
-Langkah 2 & Langkah 3
NetA = 192.168.64.0/24 s/d 192.168.64.0/24
NetB = 192.168.64.128/24 s/d 192.168.64.255/24
Net C= 192.168.65.0/25 s/d 192.168.65.31/25
NetD = 192.168.65.32/24 s/d 192.168.65.63/24
NetE = 192.168.65.64/24 s/d 192.168.65.79/24
IP sisa = 192.168.65.80 s/d 192.168.65.255 (176 ip)
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